If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2r^2-18r+9=0
a = 2; b = -18; c = +9;
Δ = b2-4ac
Δ = -182-4·2·9
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{7}}{2*2}=\frac{18-6\sqrt{7}}{4} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{7}}{2*2}=\frac{18+6\sqrt{7}}{4} $
| 8-3k=2-27 | | 180=(165-n)+n+15 | | 8x+24=3 | | 10x-46=7x | | 7/x=3/49 | | (-7x)/(15+2x)=0 | | 2^(2+2x)+3.2^x-1=0 | | n2+n-1000=0 | | 87=2y+7 | | (x+5)-2=10 | | 2x-3(5x-7)=0 | | 2(10-2x)=19x+2 | | X2+241x-9972=0 | | 3/n=n/9 | | Y+15=11-2x | | 7(p-2)-2(7-3)+2=0 | | 4(x-1)=6x-1) | | x+11=-1-x | | 2*4.19*(20-15)=x*4.19(20-15) | | 2(3c+2)=8 | | 2*20x*5=(2x)*15 | | 6b-18=24 | | 9t-27=3t | | 3(1-2x)=3(2-x) | | 4(1-2x7)=3(2-x) | | -0.03x=0 | | 3y-9=10y+1 | | 7c/5c=0 | | 8y-2(6-2y)=7y-(3y-8)2 | | 21.1w+4.6=10.9w | | 7x-1=19-x | | K^3=4k |